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4.9t^2-14t-9.8=0
a = 4.9; b = -14; c = -9.8;
Δ = b2-4ac
Δ = -142-4·4.9·(-9.8)
Δ = 388.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-\sqrt{388.08}}{2*4.9}=\frac{14-\sqrt{388.08}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+\sqrt{388.08}}{2*4.9}=\frac{14+\sqrt{388.08}}{9.8} $
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